3(x+1)^2/3=12

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Solution for 3(x+1)^2/3=12 equation: 


x in (-oo:+oo)

(3*(x+1)^2)/3 = 12 // - 12

(3*(x+1)^2)/3-12 = 0

(x+1)^2-12 = 0

(x+1)^2-12 = 0

x^2+2*x-11 = 0

x^2+2*x-11 = 0

x^2+2*x-11 = 0

DELTA = 2^2-(-11*1*4)

DELTA = 48

DELTA > 0

x = (48^(1/2)-2)/(1*2) or x = (-48^(1/2)-2)/(1*2)

x = (4*3^(1/2)-2)/2 or x = (-4*3^(1/2)-2)/2

(x-((-4*3^(1/2)-2)/2))*(x-((4*3^(1/2)-2)/2)) = 0

(x-((-4*3^(1/2)-2)/2))*(x-((4*3^(1/2)-2)/2)) = 0

( x-((-4*3^(1/2)-2)/2) )

x-((-4*3^(1/2)-2)/2) = 0 // + (-4*3^(1/2)-2)/2

x = (-4*3^(1/2)-2)/2

( x-((4*3^(1/2)-2)/2) )

x-((4*3^(1/2)-2)/2) = 0 // + (4*3^(1/2)-2)/2

x = (4*3^(1/2)-2)/2

x in { (-4*3^(1/2)-2)/2, (4*3^(1/2)-2)/2 }

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